Unitconsumed = Power in kW X numbers of hours of operation. = 59.76 units. Hence units burnt (consumed) by 3 HP motor in 24 hours will be 59.76, if the motor efficiency is 90% and motor is fully loaded. In actual, motor load will be less than full load and units consumed will be less accordingly. So, in 24 hour = 24*2.238 = 53.72 units in 24 hr.
Theenergy E in kilowatt-hours is equal to the power P consumed in kilowatts times the time T in hours. For example, let’s convert 25 kW power used over a 4-hour time period to energy in kWh. EkWh = 25 kW × 4 hours. EkWh = 100 kWh. So, 25 kW of power consumed over 4 hours is equal to 100 kWh of energy. Do you want to convert kWh to kW ?
Whenthe power factor is 1.0 (unity) or 100%, the phase angle between the current and the voltage will be 0° because cos⁻¹(1.0) = 0°. When the power factor equals zero (0), the phase angle is 90° due to the formula cos⁻¹(0) = 90°. The higher the power factor, the more efficient the system will be.
100kVA to Amps in case of 120 V (Three Phase) Formula: Amps = (kVA * 1000)/E = (100 * 1000)/ (120*1.73) = 481.69 amps. 100 kVA to Amps conversion formula with solved examples for different voltage levels in case of Single and Three phase AC circuits.
Thefull load current calculator calculates the full load current for 1-phase AC, 3-phase AC and DC loads in kW, kVA or hp. Includes step-by-step equations. Voltage (V) Load rating (kW, kVA or hp) pf. Cable Size Calculator AS/NZS 3008. Maximum Demand Calculator AS/NZS 3000. Arc Flash Calculator IEEE 1584.
Forthree phase motors, when HP is known: Where, Voltage: The phase-to-phase voltage for a 3-phase supply. Rating: The power rating of the motor in kW. Power factor (cosΦ): The rated power factor of the motor. Efficiency (η): The efficiency of the motor. Approximate FLC of single-phase motors:
TWP71. 351 236 210 325 76 439 182 95 72
5.5 kw to amps 3 phase
